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3rd Closing Merit List (in comparison format)

"SOME UPDATES ARE UPDATED TOO" Finally By the Feedback Of You People , we did a survey to find out the (EXPECTED) closing Merit Position's of 2nd Merit List ..but you will get in this post 3rd merit list in comparison format which is better even.This time merit is too low because majority of the student didn't pay the fee .
3rd list and also comparison between 2nd and 3rd list
Sr# Department 2nd 3rd
1 Mechanical Engineering(SMME) 345 345
2 Mechanical Engineering(EME) 613 wait
3 Electrical Engineering (EME) 837 849
4 Electrical Engineering (SEECS) 668 wait
5 Computer Science ( SEECS) 2473 2717
6 Computer Engineering (EME) 2127 2564
7 Software Engineering (SEECS) 1544 1549
8 Software Engineering (MCS) 1856 1936
9 Civil Engineering (SCEE) 1277 1277
10 Civil Engineering (MCE) 1621 1718
11 Chemical Engineering (SCME) 1301 wait
12 Material Engineering (SCME) 1748 2413
13 Aerospace Engineering (CAE) 974 wait
14 Avionivs Engineering (CAE) 986 wait
15 Mechatronics Engineering (EME) 1276 wait
16 Electrical Engineering (Karachi) 2212 2706
17 Mechanical Engineering (Winter Session) (Karachi) 2143 2573
18 Environmental Engineering (SCEE) 2826 3105
19 GeoInformatic Engineering (SCEE) 2957 wait
20 Electrical(Telecom) MCS 1907 2235
20 Industrial and manufacturing (PNEC) 2918 3309
21 Mechanical Engineering (PNEC) 1648 wait
Nust Business School
1 Department 2nd 3rd
2 BS Accounting and Finance 528 wait
3 BS Economics(Islamabad) 539 644
4 BS Mass Communication 602 819
5 BBA 527 539
6 Public administration 545 805
Closing Merit Position of Bachelor of Architecture/Industrial Design
1 BS Architecture(Islamabad) 64 68
2 BS Industrial Design(Islamabad) 125 144
Closing Merit Position of BS Mathematics and BS Physics
1 BS Mathematics(Islamabad) 206 427
2 BS Physics(Islamabad) 175 556
These are the EXPECTED merit positions as you people helped us in doing a survey..If anyone feels that it would need a bit amendment , he can comment below but with a Valid roll number for a proof ! It would be a great Relief for All of you .. Now You can Expect that in Which List you would be Selected .. Stay Tuned For More ..
Good Luck to Every One ..Like our page
Regards : Admin Panel

How to Find Period of Function and Equation

Period and Domain of Trigonometry function Here you find all types of ticks regarding to "Period and Domain of Trigonometry function".This is very easy chapter in trigonometric portion.
I am going to share you a simple tricks which I remembered and it helped me a lot.So let's start.

Period and Domain of Trigonometry function


→ How to find "Period" of any function

For Example-1 → Find the period of sin5x??

General formula → :we now 2 ∏ is the period of Sin.So the general formula of sinax is 2 ∏ /a.

Answer → :In above example,here a=5 so we put this into general formula(2 ∏ /a).We get 2 ∏ /5 which is the answer of this question.
For Example-2 → Find the period of tan5x??

General formula → :we now ∏ is the period of Tan.So the general formula of tanax is ∏ /a.

Answer → :In above example,here a=5 so we put this into general formula( ∏ /a).We get ∏ /5 which is the answer of this question.
→ How to find period of "Remaining Function"


1-Cot and Tan → These two function Follow the same rule because their period is ∏


2-Sin,Cosec,Cos and Sec → These two function Follow the same rule because their period is 2 ∏

→ How to find period of an "Equation Function"

For Example-3 → Find the period of sin5x +cos5x??

Trick → if the period of both function(given equation) are same then period of any one function is the period of function

Answer → The period of this equation is 2 ∏ /5.

For Example-4 → Find the period of tan5x +cos5x??

Trick → if the period of both function(given equation) are different then we first find the period of both function .After finding the period of both function we simply add it.So,we will get period of an equation


Answere → The period of this equation is 3 ∏ /5.

For Example → Find the period of sin2x +cos5x??

Trick → if the period of both function are same but answer of function is different.Like in given example period of sin2x is ∏ and cos5x is 2 ∏ /5.So,we add both the period of function.After adding the function we get the period of required equation

Answer → The period of this equation is 7 ∏ /5.
I hope you get the idea of solving these types of equations.Insh ALlah i will share you more tips which i remember.
Prepared by → :Entrytestalltime Team

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Error Expected

Equation involving two variables and Permutation

Equation involving two variables and Permutation Here you find all types of ticks regarding to "Equation involving two variables and Permutation ".This Chapter is very easy to understand and 1 question ask from this chapter.So,Friends you have to learn this chapter in order to secure good marks in any type of entry test because in entry test 2-3 questions make very large different in aggregate
I am going to share you a simple tricks which I remembered and it helped me a lot.So let's start.

1st Topic:Equation involving two variables


1st Tip

For Example → Find the value of x and y if x+y=7 and x2-xy+y2=13???

Option ↓
a).(1,0)
b).(2,1)
c).(4,3)
d).(-3,2)

How → This question can be solved within 30 second but How??

Solution → This question is solved very easily because in entry test options are given in question sheet.Simply you have to satisfy 1 option which satisfy the equation.

Answer → So,Option c will satisfy the equation if you put x=4 and y=3 you will satisfy the equation.But if you put (-3,2) in given equation,given equation will not satisfy the condition


Sometimes questions asked like this → How many roots of given equation.

Simply the degree of equation is equal to the roots of equation.

2nd Topic:Permutation


1st Tip

For Example → How many arrangements of the letters of the "Pakistan" words,taken all together,can be made ?

Tips → Count the letters.i.e.8 and count how many words are same.In above example,2 A is same whereas remaining alphabet only 1.So we divide total count alphabet/same alphabet.

Solution → So we get 8!/2!.

Answer → 20160 is correct answer ♥

Prepared by → :Entrytestalltime Team

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Error Expected

How to do Parabola shotly Tips & Tricks

HYPERBOLA,PARABOLA and ELLIPSE TIPS Here you find all types of ticks regarding to Parabola,Hyperbola And Ellipse Chapter.This chapter like the heart of Math Portion because 2-3 question ask from this chapter.So,Friends you have to learn this chapter more carefully and more successfully.
I am going to share you a simple tricks which I remembered and it helped me a lot.So let's start.

PARABOLA TIPS


1st Tip

For Example → Find the focus and vertex of x2=-24y???

Focus → First of all see in the question where is the square whether it is in x or y.After seeing the square,think (0,a)(where 0 is replaced because x2).If we have equation like this y2=-24x then we think (a,0) because here y is squared.So now we have to find a?.a is simple to find co-efficient of degree 1 is equal to 4a(-24=4a).After solving this we get a=-6.So the focus of this equation is (0,-6).

Vertex → Vertex of all these types of equation(x2=4y,x2=-4y,y2=4x,y2=-4x) is (0,0)

Directrix → Directrix is directly related to a and sign of squared value.See above example where x is squared so mean x=0(reference read focus portion) and a=-6(reference read focus portion).So we get directrix y-6=0.If we have an equation like this y2=8x(here a=2 and y=0) So x+8=0 is the directrix of this equation y2=8x


Sometimes questions asked like this → Find the equation,if focus(0,-8) ,vertex(0,0) and options are given.

Simply you have to find focus of given options if any one of the option is matched with given focus,then that will be the correct answer of given condition.

2nd Tip

For Example → Find the focus and vertex of (x-1)2=-24(y-2)???

First of all suppose x-1=X and y-2=Y.So the equation becomes X2=-24Y

Focus → =Find Focus of this equation is same as that of above i.e:(0,-6).But here you have to follow one more step as seen from this focus X=0 and Y=-6 So you have to put value of X i.e.x-1 and Y=y-2.So,we get x-1=0 and y-2=-6,by solving this we get x=1 and y=-4 so Focus becomes(1,-4).

Vertex → Vertex of this equation(X2=-24Y) is (0,0).Then,you have to follow same rule as that of focus.X=0 and Y=0 .Putting the value of X and Y.we get x-1=0 and y-2=0.By solving this we get x=1 and y=2.So the vertex of this equation becomes (1,2)

Directrix → .Here we apply same rule as that of Example-1.We have equation X2=-24Y.So here Directrix is equal to Y-6.Putting the value of Y


Sometimes questions asked like this → Find the equation,if focus(0,-8) ,vertex(0,0) and options are given.

Simply you have to find focus of given options if any one of the option is matched with given focus,then that will be the correct answer of given condition.

Prepared by → :Entrytestalltime Team

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Error Expected

KIPS FULL LENGTH PAPER



KIPS FULL LENGTH PAPER 

FULL LENGTH PAPER 2014

  1. Paper-1
  2. Paper-2
  3. Paper-3
  4. Paper-4
  5. Paper-5
  6. Paper-6
  7. Paper-7
  8. Paper-8



Remaining Paper will be uploaded tonight Thanks

Admin:Shahbaz Ahmed

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