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Here you find all types of ticks regarding to "Period and Domain of Trigonometry function".This is very easy chapter in trigonometric portion.
I am going to share you a simple tricks which I remembered and it helped me a lot.So let's start.

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Period and Domain of Trigonometry function

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For Example-1 → Find the period of sin5x??

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General formula → :we now 2 ∏ is the period of Sin.So the general formula of sinax is 2 ∏ /a.

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Answer → :In above example,here a=5 so we put this into general formula(2 ∏ /a).We get 2 ∏ /5 which is the answer of this question.

For Example-2 → Find the period of tan5x??

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General formula → :we now ∏ is the period of Tan.So the general formula of tanax is ∏ /a.

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Answer → :In above example,here a=5 so we put this into general formula( ∏ /a).We get ∏ /5 which is the answer of this question.

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1-Cot and Tan → These two function Follow the same rule because their period is ∏

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2-Sin,Cosec,Cos and Sec → These two function Follow the same rule because their period is 2 ∏

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For Example-3 → Find the period of sin5x +cos5x??

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Trick → if the period of both function(given equation) are same then period of any one function is the period of function

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Answer → The period of this equation is 2 ∏ /5.

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For Example-4 → Find the period of tan5x +cos5x??

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Trick → if the period of both function(given equation) are different then we first find the period of both function .After finding the period of both function we simply add it.So,we will get period of an equation

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Answere → The period of this equation is 3 ∏ /5.

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For Example → Find the period of sin2x +cos5x??

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Trick → if the period of both function are same but answer of function is different.Like in given example period of sin2x is ∏ and cos5x is 2 ∏ /5.So,we add both the period of function.After adding the function we get the period of required equation

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Answer → The period of this equation is 7 ∏ /5.

I hope you get the idea of solving these types of equations.Insh ALlah i will share you more tips which i remember.

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Here you find all types of ticks regarding to Parabola,Hyperbola And Ellipse Chapter.This chapter like the heart of Math Portion because 2-3 question ask from this chapter.So,Friends you have to learn this chapter more carefully and more successfully.
I am going to share you a simple tricks which I remembered and it helped me a lot.So let's start.

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PARABOLA TIPS

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For Example → Find the focus and vertex of x2=-24y???

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Focus → First of all see in the question where is the square whether it is in x or y.After seeing the square,think (0,a)(where 0 is replaced because x2).If we have equation like this y2=-24x then we think (a,0) because here y is squared.So now we have to find a?.a is simple to find co-efficient of degree 1 is equal to 4a(-24=4a).After solving this we get a=-6.So the focus of this equation is (0,-6).

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Vertex → Vertex of all these types of equation(x2=4y,x2=-4y,y2=4x,y2=-4x) is (0,0)

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Directrix → Directrix is directly related to a and sign of squared value.See above example where x is squared so mean x=0(reference read focus portion) and a=-6(reference read focus portion).So we get directrix y-6=0.If we have an equation like this y2=8x(here a=2 and y=0) So x+8=0 is the directrix of this equation y2=8x

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Sometimes questions asked like this → Find the equation,if focus(0,-8) ,vertex(0,0) and options are given.

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Simply you have to find focus of given options if any one of the option is matched with given focus,then that will be the correct answer of given condition.

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For Example → Find the focus and vertex of (x-1)2=-24(y-2)???

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First of all suppose x-1=X and y-2=Y.So the equation becomes X2=-24Y

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Focus → =Find Focus of this equation is same as that of above i.e:(0,-6).But here you have to follow one more step as seen from this focus X=0 and Y=-6 So you have to put value of X i.e.x-1 and Y=y-2.So,we get x-1=0 and y-2=-6,by solving this we get x=1 and y=-4 so Focus becomes(1,-4).

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Vertex → Vertex of this equation(X2=-24Y) is (0,0).Then,you have to follow same rule as that of focus.X=0 and Y=0 .Putting the value of X and Y.we get x-1=0 and y-2=0.By solving this we get x=1 and y=2.So the vertex of this equation becomes (1,2)

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Directrix → .Here we apply same rule as that of Example-1.We have equation X2=-24Y.So here Directrix is equal to Y-6.Putting the value of Y

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Sometimes questions asked like this → Find the equation,if focus(0,-8) ,vertex(0,0) and options are given.

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Simply you have to find focus of given options if any one of the option is matched with given focus,then that will be the correct answer of given condition.

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